Symphony No. 10 (Shostakovich)
Symphony No. 10 in E minor, Op. 93, by Dmitri Shostakovich was first played in Leningrad by the Leningrad Philharmonic on 17 December 1953. Yevgeny Mravinsky was the conductor.[1]
Form
The symphony has four parts, also called movements:
- Moderato
- Allegro
- Allegretto – Largo –Più mosso
- Andante – Allegro – L'istesso tempo
Instruments
The symphony is written for an orchestra with:[2]
- Percussion
- Timpani
- Snare drum
- Bass drum
- Cymbals
- Triangle
- Tambourine
- Tam-tam
- Xylophone
- Strings
- 1st Violins
- 2nd Violins
- Violas
- Cellos
- Double basses
References
- ↑ Wilson, Elizabeth (1994) p. 262. Shostakovich: A Life Remembered. Princeton University Press. ISBN 0-691-04465-1.
- ↑ "New York Philharmonic | Digital Archives. Dmitri Shostakovich – Symphony No.10 in E minor (ID: 7533)". New York Philharmonic | Digital Archives. Archived from the original on 22 September 2024. Retrieved 21 September 2024.